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Our next Part-Time JavaScript Course starts in December. Save $200 if you register before November 15!By the end of this chapter, you should be able to:

- Describe big-O notation
- Evaluate the runtime of algorithms using big-O notation
- Compare fastest to slowest asymptotic complexities of common runtimes (e.g. O(1), O(log(n)), O(n), O(nlog(n)), O(n
^{2}), etc). - Explain the difference between time complexity and space complexity

When you are working on a solution to a problem, often times you will want to see how "fast" your solution is. Unfortunately, there are many variables that go into the speed of your program. For example, the hardware on your computer, the data set that you're using, the other programs running on the computer, and even the temperature in the room can all affect the speed of a program. So simply using a timer to measure the speed of a program can be useful, but it may not always be a reliable way to compare one implementation to another.

A more theoretical way of comparing one algorithm to another is called **big O** notation. Big O notation is a concept borrowed from mathematics that gives you an approximate upper bound on the runtime of your algorithm based on the size of the data set that the algorithm will use. If you're curious about a rigorous definition of the notation, check out this article. For now, we'll focus on building an intuitive understanding of the notation so that you can apply it effectively.

To get started with Big O notation, it is useful to understand what is important and what is not. There are a couple of rules with the notation to remember:

Keeping those rules in mind, the following are equivalent:

- O(500 * n) --> O(n)
- O(99999999999) --> O(1)
- O(10*n
^{2}+ 5n + 20) --> O(n^{2}) - O(n * n) --> O(n
^{2}) - O(n*log(n) + 30000 * n) --> O(n * log(n))

Notice that in all examples, constant values are replaced with 1, and all smaller components that are added are ignored.

Next, let's learning about analyzing an algorithm using Big O notation:

**O(1)**

The following functions are **O(1)** or **constant time** because the algorithm is not dependent on a variable size data set. In other words, regardless of the input size, the runtime of the algorithm will not grow beyond some constant size. (In many cases, it will be roughly the same regardless of the input).

function add(num1, num2, num3) { return num1 + num2 + num3; }

In the above example, `add`

requires two addition operations. The size of the numbers doesn't affect how many additions need to be performed, so in this case the runtime isn't dependent on the size of the inputs.

function sayHello() { for (var i = 0; i < 100; i++) { console.log("Hello"); } }

`sayHello`

logs a message to the console 100 times whenever it is called. This function is also O(1); it doesn't even have any inputs!

function logMultiples(num) { for (var i = 0; i < 10; i++) { console.log(i * num); } }

The `logMultiples`

function logs the first ten multiples of the input to the console. Regardless of the size of `num`

, however, only the first ten multiples will ever be logged. In other words, the runtime once again does not depend on the size of the input, and this function is also O(1).

**O(n)**

The following algorithms are **O(n)**, or **linear time**, because the data set is iterated over approximately one time:

function sayHello(numberOfTimes) { for (var i = 0; i < numberOfTimes; i++) { console.log("Hello"); } }

Unlike our previous `sayHello`

function, this one takes an argument, which controls how many times `Hello`

gets logged to the console. In this case, the runtime of the function should be roughly proportional to the size of `numberOfTimes`

. For example, it should take roughly ten times as long to log `Hello`

1,000 times as it does to log `Hello`

100 times. Setting `numberOfTimes`

equal to `n`

, the size of the input, this means that the runtime of `sayHello`

is O(n).

function doubleThenTriple(numbers) { var doubled = numbers.map(function(num) { return num * 2; }); return doubled.map(function(num) { return num * 3; }); }

In the above example we map over the data set twice. So you could say the runtime is **O(n + n)** or **O(2*n)**. However, in big O notation, constants are ignored. So, **O(2*n)** is equivalent to **O(n)**. What matters is that the runtime scales in proportion to the input size, not the details of the proportional relationship.

**O(n ^{2})**

function allPairs(arr) { var pairs = []; for (var i = 0; i < arr.length; i++) { for (var j = i + 1; j < arr.length; j++) { pairs.push([arr[i], arr[j]]); } } return pairs; }

function bubbleSort(arr) { var len = arr.length; var lastSwap; var temp while (len != 0) { lastSwap = 0; for (var i = 1; i < len; i++) { if (arr[i - 1] > arr[i]) { // Swap the two elements temp = arr[i-1]; arr[i-1] = arr[i]; arr[i] = temp; lastSwap = i; } } len = lastSwap; } }

In these two examples, within each element of the array, we are iterating over all elements again. Therefore, the runtime is O(n * n) or **O(n ^{2})**.

It's a helpful rule of thumb that in general, if you see nested loops, the runtime will be O(n^{levels of nesting}). In other words, a function with a single `for`

loop will be O(n), a function with a loop inside of a loop will be O(n^{2}), a function with a loop inside of a loop inside of a loop will be O(n^{3),} and so on. However, this rule of thumb doesn't always hold, as the following examples show:

function logMultiples(n) { for (var num1 = 1; num1 <= n; num1++) { for (var num2 = 1; num2 <= n; num2++) { console.log(num1 * num2); } } } function logSomeMultiples(n) { for (var num1 = 1; num1 < n=; num1++) { for (var num2 = 1; num2 <= Math.min(n, 10); num2++) { console.log(num1 * num2); } } }

The first function, `logMultiples`

, is O(n^{2}). When `n`

is 1, the function logs 1 multiple; when `n`

is 2, the function logs 4 multiples; when `n`

is 3, the function logs 9 multiples, and so on.

What about the second function, `logSomeMultiples`

? It might seem like this function should be O(n^{2}) as well, because of the inner loop. However, the runtime of the inner loop is not proportional to n! The inner loop will run a maximum of 10 times, so it is actually an O(1) operation. This means that the outer loop, which is still O(n), performs an O(1) operation for each value of `num1`

. Therefore, `logSomeMultiples`

is itself O(n), not O(n^{2}).

In the following chart the X axis represents the size of the input (size of the array of data for example) and the Y axis represents a unit of time to run the program.

**Legend**

Color | Big O Runtime |
---|---|

Blue | O(1) |

Red | O(log(n)) |

Green | O(n) |

Yellow | O(n*log(n)) |

Purple | O(n^{2}) |

As you can see from the chart, as the input size goes up, the performance of these algorithms is dramatically different.

So far we've only been talking about the runtime of different algorithms using Big O Notation. This is often referred to as analyzing the **time complexity** of the algorithm.

But Big O isn't just used to talk about the time it takes our programs to run; it's also used to talk about how much space (i.e. memory) our program requires. This is often referred to as analyzing the **space complexity** of the algorithm.

Very often we're concerned primarily with **auxiliary space complexity**, that is, how much additional memory does the algorithm require beyond what needs to be allocated for the inputs themselves?

Let's look at a couple of examples:

function total(array) { var total = 0; for (var i = 0; i < array.length; i++) { total += array[i]; } return total; }

In this example, `total`

takes one input, which is an array. Let's let `n`

denote the length of the array. Note that the time complexity of `total`

is O(n), since we're looping through the array once and adding to the total. However, the space complexity is just O(1), since we only require one additional unit of space, for the number stored in `total`

.

Here's another example:

function double(array) { var newArray = []; for (var i = 0; i < array.length; i++) { newArray.push(2 * array[i]); } return newArray; }

Here, our function `double`

takes each element of the input array, doubles it, and returns a new array of doubled values. In this case, both the time and space complexities are O(n). Space complexity is larger in this case because we need n additional units of space: one for each element in the original array.

When you're ready, move on to Big O Exercises